eq-sb>b

Theorem.

Arguments:

(st), (sv), (pr),

Assertions:

(()([/]))

Proof:

Hyp	Ref	Line	Expr
	eqt-sb	1	(()([/][/]))
	sbid	2	([/])
2	ax1	3	(()([/]))
1, 3	<>bitrd	4	(()([/]))