sb-bi<

Theorem.

Arguments:

y (st), x (sv), phi (pr), psi (pr), chi (pr),

Hypotheses:

([y/x]phileftrightarrowpsi)

Assertions:

([y/x](phileftrightarrowchi)leftrightarrow(psileftrightarrow[y/x]chi))

Proof:

Hyp Ref Line Expr
Hypo1([y/x]phileftrightarrowpsi)
sb-bi2([y/x](phileftrightarrowchi)leftrightarrow([y/x]phileftrightarrow[y/x]chi))
1bi.bldbi<3(([y/x]phileftrightarrow[y/x]chi)leftrightarrow(psileftrightarrow[y/x]chi))
2, 3bitr4([y/x](phileftrightarrowchi)leftrightarrow(psileftrightarrow[y/x]chi))