sb-bi>

Theorem.

Arguments:

y (st), x (sv), phi (pr), psi (pr), chi (pr),

Hypotheses:

([y/x]phileftrightarrowpsi)

Assertions:

([y/x](chileftrightarrowphi)leftrightarrow([y/x]chileftrightarrowpsi))

Proof:

Hyp Ref Line Expr
Hypo1([y/x]phileftrightarrowpsi)
sb-bi2([y/x](chileftrightarrowphi)leftrightarrow([y/x]chileftrightarrow[y/x]phi))
1bi.bldbi>3(([y/x]chileftrightarrow[y/x]phi)leftrightarrow([y/x]chileftrightarrowpsi))
2, 3bitr4([y/x](chileftrightarrowphi)leftrightarrow([y/x]chileftrightarrowpsi))