sb-eqat>

Theorem.

Arguments:

x (st), y (sv), z (st),

Distinct variable conditions:

(x, y),

Assertions:

([z/y](xeqy)leftrightarrow(xeqz))

Proof:

Hyp Ref Line Expr
sb-eqat<1([z/y](yeqx)leftrightarrow(zeqx))
com2((xeqy)leftrightarrow(yeqx))
2bi.bldsb3([z/y](xeqy)leftrightarrow[z/y](yeqx))
com4((xeqz)leftrightarrow(zeqx))
1, 3, 4<2bitr5([z/y](xeqy)leftrightarrow(xeqz))