eqt<>pd

Theorem.

Arguments:

(obj), (obj), (obj), (obj), (pr),

Hypotheses:

(())

(())

Assertions:

((()()))

Proof:

Hyp	Ref	Line	Expr
	Hypo	1	(())
		2	(())
2	eqt<p	3	((()()))
1	eqt>p	4	((()()))
3, 4	bitrd	5	((()()))