bv-∨

Theorem.

Arguments:

phi (pr), psi (pr), x (sv),

Hypotheses:

(x bound in psi)
(x bound in phi)

Assertions:

(x bound in (phiveepsi))

Proof:

Hyp Ref Line Expr
Hypo1(x bound in psi)
2(x bound in phi)
2bv-¬3(x bound in lnotphi)
1, 3bv-→4(x bound in (lnotphitopsi))
df-or5((phiveepsi)leftrightarrow(lnotphitopsi))
4, 5bvdef6(x bound in (phiveepsi))