fv-exx

Theorem.

Arguments:

x (sv), phi (pr),

Assertions:

(existsxphitoforallxexistsxphi)

Proof:

Hyp Ref Line Expr
fv-nalx1(x bound in lnotforallxlnotphi)
1df-Bvp2(lnotforallxlnotphitoforallxlnotforallxlnotphi)
df-ex3(existsxphileftrightarrowlnotforallxlnotphi)
3eqt-∀-i4(forallxexistsxphileftrightarrowforallxlnotforallxlnotphi)
2, 3, 4<imtr5(existsxphitoforallxexistsxphi)