>bi

Theorem.

Arguments:

phi (pr), psi (pr),

Assertions:

((phitopsi)to((psitophi)to(phileftrightarrowpsi)))

Proof:

Hyp Ref Line Expr
df-bi1lnot(((phileftrightarrowpsi)tolnot((phitopsi)tolnot(psitophi)))tolnot(lnot((phitopsi)tolnot(psitophi))to(phileftrightarrowpsi)))
1pm3.27im2(lnot((phitopsi)tolnot(psitophi))to(phileftrightarrowpsi))
2exp-pre3((phitopsi)to((psitophi)to(phileftrightarrowpsi)))