ancom

Theorem.

Arguments:

phi (pr), psi (pr),

Assertions:

((phiwedgepsi)leftrightarrow(psiwedgephi))

Proof:

Hyp Ref Line Expr
siman<1((phiwedgepsi)tophi)
siman>2((phiwedgepsi)topsi)
1, 2jca3((phiwedgepsi)to(psiwedgephi))
siman<4((psiwedgephi)topsi)
siman>5((psiwedgephi)tophi)
4, 5jca6((psiwedgephi)to(phiwedgepsi))
3, 6>bii7((phiwedgepsi)leftrightarrow(psiwedgephi))