bicom

Theorem.

Arguments:

phi (pr), psi (pr),

Assertions:

((phileftrightarrowpsi)leftrightarrow(psileftrightarrowphi))

Proof:

Hyp Ref Line Expr
ancom1(((phitopsi)wedge(psitophi))leftrightarrow((psitophi)wedge(phitopsi)))
dfbi2((phileftrightarrowpsi)leftrightarrow((phitopsi)wedge(psitophi)))
dfbi3((psileftrightarrowphi)leftrightarrow((psitophi)wedge(phitopsi)))
1, 2, 3<2bitr4((phileftrightarrowpsi)leftrightarrow(psileftrightarrowphi))