∃∨∃mo

Theorem.

Arguments:

x (sv), phi (pr),

Assertions:

(existsxphivee_em1xphi)

Proof:

Hyp Ref Line Expr
<neg1(lnotexistsxphito(existsxphito_e1xphi))
df-∃mo2(_em1xphileftrightarrow(existsxphito_e1xphi))
1, 2brpi22<3(lnotexistsxphito_em1xphi)
3df-or4(existsxphivee_em1xphi)