eqt-∃mo-d

Theorem.

Arguments:

(sv), (pr), (pr), (pr),

Hypotheses:

(())

( bound in )

Assertions:

(())

Proof:

Hyp	Ref	Line	Expr
	Hypo	1	(())
		2	( bound in )
1, 2	bi.bldexd	3	(())
1, 2	eqt-∃1-d	4	(())
3, 4	bi.bldim<>d	5	((()()))
	df-∃mo	6	(())
	df-∃mo	7	(())
5, 6, 7	<2bitrg	8	(())